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Select the outlier in the data set.\newline2,76,80,82,83,88,92,942, 76, 80, 82, 83, 88, 92, 94\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease

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Q. Select the outlier in the data set.\newline2,76,80,82,83,88,92,942, 76, 80, 82, 83, 88, 92, 94\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease
  1. Identify Outlier: Step 11: Identify the outlier in the data set.\newlineData set: 2,76,80,82,83,88,92,942, 76, 80, 82, 83, 88, 92, 94\newlineTo find the outlier, look for a number that is significantly different from the rest.\newlineOutlier: 22
  2. Calculate Mean Original: Step 22: Calculate the mean of the original data set.\newlineMean = (2+76+80+82+83+88+92+94)/8(2 + 76 + 80 + 82 + 83 + 88 + 92 + 94) / 8\newlineMean = 597/8597 / 8\newlineMean = 74.62574.625
  3. Calculate Mean Without Outlier: Step 33: Calculate the mean of the data set without the outlier.\newlineNew data set: 76,80,82,83,88,92,9476, 80, 82, 83, 88, 92, 94\newlineMean = (76+80+82+83+88+92+94)/7(76 + 80 + 82 + 83 + 88 + 92 + 94) / 7\newlineMean = 595/7595 / 7\newlineMean = 8585
  4. Compare Means: Step 44: Compare the two means to determine if the mean increases or decreases after removing the outlier.\newlineOriginal mean: 74.62574.625\newlineNew mean: 8585\newlineSince 8585 is greater than 74.62574.625, removing the outlier increases the mean.

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