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Select the outlier in the data set.\newline2,63,65,66,68,70,72,802, 63, 65, 66, 68, 70, 72, 80\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease

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Q. Select the outlier in the data set.\newline2,63,65,66,68,70,72,802, 63, 65, 66, 68, 70, 72, 80\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease
  1. Identify Outlier: Identify the outlier in the given data set.\newlineThe data set is: 2,63,65,66,68,70,72,802, 63, 65, 66, 68, 70, 72, 80.\newlineAn outlier is a data point that is significantly different from the rest of the data. We can visually inspect the data set and see that the number 22 is much smaller than all other numbers, which are relatively close to each other.
  2. Calculate Mean with Outlier: Calculate the mean of the data set with the outlier included.\newlineTo find the mean, add all the numbers together and divide by the number of data points.\newlineMean = (2+63+65+66+68+70+72+80)/8(2 + 63 + 65 + 66 + 68 + 70 + 72 + 80) / 8\newlineMean = (486)/8(486) / 8\newlineMean = 60.7560.75
  3. Calculate Mean without Outlier: Calculate the mean of the data set without the outlier. Remove the outlier 22 and then add the remaining numbers together and divide by the new number of data points. Mean without outlier = (63+65+66+68+70+72+80)/7(63 + 65 + 66 + 68 + 70 + 72 + 80) / 7 Mean without outlier = (484)/7(484) / 7 Mean without outlier = 69.1469.14 (rounded to two decimal places)
  4. Compare Mean Difference: Compare the two means to determine if the mean would increase or decrease if the outlier were removed.\newlineThe mean with the outlier is 60.7560.75, and the mean without the outlier is 69.1469.14. Since 69.1469.14 is greater than 60.7560.75, removing the outlier increases the mean.

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