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Select the outlier in the data set.\newline2,61,63,64,65,67,72,80,902, 61, 63, 64, 65, 67, 72, 80, 90\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease

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Q. Select the outlier in the data set.\newline2,61,63,64,65,67,72,80,902, 61, 63, 64, 65, 67, 72, 80, 90\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease
  1. Identify Outlier: Step 11: Identify the outlier in the data set.\newlineData set: 2,61,63,64,65,67,72,80,902, 61, 63, 64, 65, 67, 72, 80, 90.\newlineOutliers are values that are much smaller or larger than the rest of the data. Here, 22 is much smaller than all other numbers.
  2. Calculate Mean with Outlier: Step 22: Calculate the mean of the data set including the outlier.\newlineMean = (2+61+63+64+65+67+72+80+90)/9(2 + 61 + 63 + 64 + 65 + 67 + 72 + 80 + 90) / 9\newlineMean = 564/9564 / 9\newlineMean = 62.6762.67
  3. Calculate Mean without Outlier: Step 33: Calculate the mean of the data set without the outlier.\newlineMean without outlier = 61+63+64+65+67+72+80+908\frac{61 + 63 + 64 + 65 + 67 + 72 + 80 + 90}{8}\newlineMean without outlier = 5628\frac{562}{8}\newlineMean without outlier = 70.2570.25
  4. Compare Mean Changes: Step 44: Compare the two means to determine if the mean increases or decreases when the outlier is removed.\newlineMean with outlier = 62.6762.67\newlineMean without outlier = 70.2570.25\newlineSince 70.2570.25 is greater than 62.6762.67, removing the outlier increases the mean.

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