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Select the outlier in the data set.\newline19,29,45,52,53,55,60,62,36819, 29, 45, 52, 53, 55, 60, 62, 368\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease

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Q. Select the outlier in the data set.\newline19,29,45,52,53,55,60,62,36819, 29, 45, 52, 53, 55, 60, 62, 368\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease
  1. Identify Outlier: Identify the outlier in the data set.\newlineData set: 19,29,45,52,53,55,60,62,36819, 29, 45, 52, 53, 55, 60, 62, 368\newlineOutliers are values that are much higher or lower than the rest of the data. 368368 is significantly higher than all other values.
  2. Calculate Mean with Outlier: Calculate the mean of the data set including the outlier.\newlineMean = (19+29+45+52+53+55+60+62+368)/9(19 + 29 + 45 + 52 + 53 + 55 + 60 + 62 + 368) / 9\newlineMean = 743/9743 / 9\newlineMean = 82.5682.56
  3. Calculate Mean without Outlier: Calculate the mean of the data set without the outlier.\newlineMean without outlier = (19+29+45+52+53+55+60+62)/8(19 + 29 + 45 + 52 + 53 + 55 + 60 + 62) / 8\newlineMean without outlier = 375/8375 / 8\newlineMean without outlier = 46.87546.875
  4. Compare Mean Change: Compare the means to determine if the mean increases or decreases when the outlier is removed.\newlineMean with outlier = 82.5682.56\newlineMean without outlier = 46.87546.875\newlineRemoving the outlier decreases the mean.

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