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Select the outlier in the data set.\newline16,20,22,33,36,43,47,24816, 20, 22, 33, 36, 43, 47, 248\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease

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Q. Select the outlier in the data set.\newline16,20,22,33,36,43,47,24816, 20, 22, 33, 36, 43, 47, 248\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease
  1. Identify Outlier: Identify the outlier in the given data set.\newlineThe data set is: 16,20,22,33,36,43,47,24816, 20, 22, 33, 36, 43, 47, 248.\newlineAn outlier is a data point that is significantly different from the rest of the data. We can often spot an outlier by looking for a number that is much larger or smaller than the rest.\newlineIn this case, 248248 is much larger than all other numbers in the set, so it is the outlier.
  2. Calculate Mean with Outlier: Calculate the mean of the data set with the outlier included.\newlineTo find the mean, add all the numbers together and then divide by the number of data points.\newlineMean = (16+20+22+33+36+43+47+248)/8(16 + 20 + 22 + 33 + 36 + 43 + 47 + 248) / 8\newlineMean = 465/8465 / 8\newlineMean 58.125\approx 58.125
  3. Calculate Mean without Outlier: Calculate the mean of the data set without the outlier.\newlineRemove the outlier (248248) and then calculate the mean of the remaining numbers.\newlineMean without outlier = (16+20+22+33+36+43+47)/7(16 + 20 + 22 + 33 + 36 + 43 + 47) / 7\newlineMean without outlier = 217/7217 / 7\newlineMean without outlier 31\approx 31
  4. Compare Mean Changes: Compare the two means to determine if the mean would increase or decrease upon the removal of the outlier. The mean with the outlier is approximately 58.12558.125, and the mean without the outlier is approximately 3131. Since the mean without the outlier is less than the mean with the outlier, the mean would decrease if the outlier were removed.

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