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Select the outlier in the data set.\newline11,18,20,21,22,23,25,22611, 18, 20, 21, 22, 23, 25, 226\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease

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Q. Select the outlier in the data set.\newline11,18,20,21,22,23,25,22611, 18, 20, 21, 22, 23, 25, 226\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease
  1. Identify Outlier: Step 11: Identify the outlier in the data set.\newlineData set: 11,18,20,21,22,23,25,22611, 18, 20, 21, 22, 23, 25, 226\newlineLooking at the numbers, 226226 stands out as it is much higher than the rest of the values.
  2. Calculate Mean Original: Step 22: Calculate the mean of the original data set.\newlineMean = (11+18+20+21+22+23+25+226)/8(11 + 18 + 20 + 21 + 22 + 23 + 25 + 226) / 8\newlineMean = 366/8366 / 8\newlineMean = 45.7545.75
  3. Calculate Mean Without Outlier: Step 33: Calculate the mean of the data set without the outlier.\newlineNew data set without 226226: 11,18,20,21,22,23,2511, 18, 20, 21, 22, 23, 25\newlineMean = (11+18+20+21+22+23+25)/7(11 + 18 + 20 + 21 + 22 + 23 + 25) / 7\newlineMean = 140/7140 / 7\newlineMean = 2020
  4. Compare Means: Step 44: Compare the two means to determine if the mean increases or decreases after removing the outlier.\newlineOriginal mean: 45.7545.75\newlineNew mean without outlier: 2020\newlineSince 2020 is less than 45.7545.75, removing the outlier decreases the mean.

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