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Select the outlier in the data set.\newline1,68,70,71,73,76,82,921, 68, 70, 71, 73, 76, 82, 92\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease

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Identify an outlier and describe the effect of removing itright chevron icon

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Q. Select the outlier in the data set.\newline1,68,70,71,73,76,82,921, 68, 70, 71, 73, 76, 82, 92\newlineIf the outlier were removed from the data set, would the mean increase or decrease?\newlineChoices:\newline(A)increase\newline(B)decrease
  1. Identify Outlier: Identify the outlier in the given data set: 1,68,70,71,73,76,82,921, 68, 70, 71, 73, 76, 82, 92. An outlier is a data point that is significantly different from the other data points in a set. We can often spot an outlier by looking for a number that is much smaller or larger than the rest of the numbers in the set.
  2. Spot Outlier: Looking at the data set, 11 is much smaller than all the other numbers, which are all above 6868. Therefore, 11 is the outlier in this data set.
  3. Calculate Mean with Outlier: Now, let's calculate the mean of the data set with the outlier included:\newlineMean with outlier = (1+68+70+71+73+76+82+92)/8(1 + 68 + 70 + 71 + 73 + 76 + 82 + 92) / 8\newlineMean with outlier = 533/8533 / 8\newlineMean with outlier = 66.62566.625
  4. Calculate Mean without Outlier: Next, calculate the mean of the data set without the outlier:\newlineMean without outlier = (68+70+71+73+76+82+92)/7(68 + 70 + 71 + 73 + 76 + 82 + 92) / 7\newlineMean without outlier = 532/7532 / 7\newlineMean without outlier = 7676
  5. Compare Means: Compare the two means to determine if the mean would increase or decrease with the removal of the outlier:\newlineMean with outlier = 66.62566.625\newlineMean without outlier = 7676\newlineSince 7676 is greater than 66.62566.625, the mean would increase if the outlier were removed.

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