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Question $15$ of $38$ ( $1$ point) I Question Attempt: $1$ of $1$ $\newline$ Evaluate the expression when $b=14$ and $c=8$ . $\newline$ $c^{2}+4(b-c)^{2}$ $\newline$ Simplify your answer as much as possible.

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Find the magnitude of a three-dimensional vector

Full solution

Q. Question

15

of

38

(

1

point) I Question Attempt:

1

of

1

\newline

Evaluate the expression when

b=14

and

c=8

.

\newline

c^{2}+4(b-c)^{2}

\newline

Simplify your answer as much as possible.

Substitute and Calculate: Substitute $b=14$ and $c=8$ into the expression to get $8^{2}+4(14-8)^{2}$ . $\newline$ Calculate the square of $c$ , which is $8^2$ . $\newline$ $8^2 = 64$ .
Calculate Square and Difference: Calculate the difference inside the parentheses: $14 - 8$ . $14 - 8 = 6$ .
Calculate Square of Difference: Calculate the square of the difference: $6^2$ . $6^2 = 36$ .
Multiply and Add: Multiply the square of the difference by $4$ : $4 \times 36$ . $4 \times 36 = 144$ . Now add this to the square of $c$ : $64 + 144$ . $64 + 144 = 208$ .
Final Value: The final value of the expression is $208$ . This is the simplified answer to the given expression with the values $b=14$ and $c=8$ .

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