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Complete the equation of the line through $(6,-6)$ and $(8,8)$ . Use exact numbers. $y=$

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Find the magnitude of a three-dimensional vector

Full solution

Q. Complete the equation of the line through

(6,-6)

and

(8,8)

. Use exact numbers.

y=

Find the Slope: Find the slope (m) of the line using the formula: $\newline$ $m = \frac{y_2 - y_1}{x_2 - x_1}$ $\newline$ $m = \frac{8 - (-6)}{8 - 6}$ $\newline$ $m = \frac{8 + 6}{2}$ $\newline$ $m = \frac{14}{2}$ $\newline$ $m = 7$
Point-Slope Form: Use the point-slope form of the line equation: $\newline$ $y - y_1 = m(x - x_1)$ $\newline$ $y - (-6) = 7(x - 6)$ $\newline$ $y + 6 = 7(x - 6)$
Slope-Intercept Form: Simplify the equation to get the slope-intercept form (y = mx + b): $\newline$ $y + 6 = 7x - 42$ $\newline$ $y = 7x - 42 - 6$ $\newline$ $y = 7x - 48$

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