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Point
J is located at -3 . Points
K and
L are each 8 units away from Point
J. Where are
K and
L located?

K=◻quadL=◻

Point $\mathrm{J}$ is located at $-3$ . Points $\mathrm{K}$ and $\mathrm{L}$ are each $8$ units away from Point $\mathrm{J}$ . Where are $\mathrm{K}$ and $\mathrm{L}$ located? $\newline$ $\mathrm{K}=\square \quad \mathrm{L}=\square$

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Transformations of functions

Full solution

Q. Point

\mathrm{J}

is located at

-3

. Points

\mathrm{K}

and

\mathrm{L}

are each

8

units away from Point

\mathrm{J}

. Where are

\mathrm{K}

and

\mathrm{L}

located?

\newline

\mathrm{K}=\square \quad \mathrm{L}=\square

Understand the problem: Understand the problem. $\newline$ We need to find the locations of Points $K$ and $L$ , which are both $8$ units away from Point $J$ on a number line. Point $J$ is at $-3$ .
Determine Point K: Determine the location of Point K. $\newline$ Since Point K is $8$ units away from Point J, it can be either $8$ units to the left or $8$ units to the right of Point J. If we move to the left, we subtract $8$ from $-3$ . $\newline$ Calculation: $K = -3 - 8 = -11$
Determine Point L: Determine the location of Point L. $\newline$ Similarly, Point L is also $8$ units away from Point J. If we move to the right, we add $8$ to $-3$ . $\newline$ Calculation: $L = -3 + 8 = 5$

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Question

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\newline

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4

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\newline

7

is incorrect. Tess didn't account for adding

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\newline

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\newline

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\newline

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\newline

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