Q. Point H is located at (2,−7).Select all of the following that are 7 units from point H.Choose all answers that apply:(A) x-axis(B) (−5,−7)(C) (−7,7)
Distance Formula Explanation: To determine which points are 7 units away from point H, we need to consider the distance formula, which is the square root of the sum of the squares of the differences in the x-coordinates and y-coordinates. The distance d between two points (x1,y1) and (x2,y2) is given by:d=((x2−x1)2+(y2−y1)2)We are looking for points where this distance equals 7.
Consider X-Axis: Let's first consider option A, the x-axis. The x-axis has a y-coordinate of 0. To be 7 units away from point H on the x-axis, we need to find an x-coordinate such that the distance from H to this point on the x-axis is 7. This means we need to solve the equation:7=((x−2)2+(0−(−7))2)
Check Option B: Simplifying the equation, we get:7=((x−2)2+72)7=((x−2)2+49)Squaring both sides to remove the square root gives us:49=(x−2)2+490=(x−2)2x−2=0x=2This means that the point on the x-axis that is 7 units away from H is (2,0), which is not an option given. Therefore, option A is incorrect.
Check Option C: Now let's consider option B, which is the point (−5,−7). We will use the distance formula to check if it is 7 units away from point H.d=((−5−2)2+(−7−(−7))2)d=(−7)2+02d=49d=7Since the distance is indeed 7, option B is correct.
Check Option C: Now let's consider option B, which is the point (−5,−7). We will use the distance formula to check if it is 7 units away from point H.d=((−5−2)2+(−7−(−7))2)d=(−7)2+02d=49d=7Since the distance is indeed 7, option B is correct.Finally, let's consider option C, which is the point (−7,7). Again, we will use the distance formula to check if it is 7 units away from point H.d=((−7−2)2+(7−(−7))2)d=(−9)2+(14)2d=(81+196)d=(277)Since 277 is not equal to 7, option C is incorrect.