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Point 
H is located at 
(2,-7).
Select all of the following that are 7 units from point 
H.
Choose all answers that apply:
A 
x-axis
B 
(-5,-7)
c 
(-7,7)

Point H H is located at (2,7) (2,-7) .\newlineSelect all of the following that are 77 units from point H H .\newlineChoose all answers that apply:\newline(A) x x -axis\newline(B) (5,7) (-5,-7) \newline(C) (7,7) (-7,7)

Full solution

Q. Point H H is located at (2,7) (2,-7) .\newlineSelect all of the following that are 77 units from point H H .\newlineChoose all answers that apply:\newline(A) x x -axis\newline(B) (5,7) (-5,-7) \newline(C) (7,7) (-7,7)
  1. Distance Formula Explanation: To determine which points are 77 units away from point HH, we need to consider the distance formula, which is the square root of the sum of the squares of the differences in the xx-coordinates and yy-coordinates. The distance dd between two points (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) is given by:\newlined=((x2x1)2+(y2y1)2)d = \sqrt{((x_2 - x_1)^2 + (y_2 - y_1)^2)}\newlineWe are looking for points where this distance equals 77.
  2. Consider X-Axis: Let's first consider option A, the x-axis. The x-axis has a y-coordinate of 00. To be 77 units away from point H on the x-axis, we need to find an x-coordinate such that the distance from H to this point on the x-axis is 77. This means we need to solve the equation:\newline7=((x2)2+(0(7))2)7 = \sqrt{((x - 2)^2 + (0 - (-7))^2)}
  3. Check Option B: Simplifying the equation, we get:\newline7=((x2)2+72)7 = \sqrt{((x - 2)^2 + 7^2)}\newline7=((x2)2+49)7 = \sqrt{((x - 2)^2 + 49)}\newlineSquaring both sides to remove the square root gives us:\newline49=(x2)2+4949 = (x - 2)^2 + 49\newline0=(x2)20 = (x - 2)^2\newlinex2=0x - 2 = 0\newlinex=2x = 2\newlineThis means that the point on the x-axis that is 77 units away from H is (2,0)(2, 0), which is not an option given. Therefore, option A is incorrect.
  4. Check Option C: Now let's consider option B, which is the point (5,7)(-5, -7). We will use the distance formula to check if it is 77 units away from point H.\newlined=((52)2+(7(7))2)d = \sqrt{((-5 - 2)^2 + (-7 - (-7))^2)}\newlined=(7)2+02d = \sqrt{(-7)^2 + 0^2}\newlined=49d = \sqrt{49}\newlined=7d = 7\newlineSince the distance is indeed 77, option B is correct.
  5. Check Option C: Now let's consider option B, which is the point (5,7)(-5, -7). We will use the distance formula to check if it is 77 units away from point H.d=((52)2+(7(7))2)d = \sqrt{((-5 - 2)^2 + (-7 - (-7))^2)}d=(7)2+02d = \sqrt{(-7)^2 + 0^2}d=49d = \sqrt{49}d=7d = 7Since the distance is indeed 77, option B is correct.Finally, let's consider option C, which is the point (7,7)(-7, 7). Again, we will use the distance formula to check if it is 77 units away from point H.d=((72)2+(7(7))2)d = \sqrt{((-7 - 2)^2 + (7 - (-7))^2)}d=(9)2+(14)2d = \sqrt{(-9)^2 + (14)^2}d=(81+196)d = \sqrt{(81 + 196)}d=(277)d = \sqrt{(277)}Since 277\sqrt{277} is not equal to 77, option C is incorrect.

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