Express the radical using the imaginary unit, i. Express your answer in simplified form. +-sqrt(-80)=+-

Expressing sqrt(-80) as a product: Express ±sqrt(-80) as the product of square roots and sqrt(-1). ±sqrt(-80) = ±sqrt(-1 * 80)Factoring 80 into 16 * 5: Factor 80 into 16 * 5, since 16 is a perfect square. ±sqrt(-80) = ±sqrt(-1 * 16 * 5)Expressing sqrt(-1) as ±i: Express ±sqrt(-1) as ±i and take the square root of 16. ±sqrt(-80) = ±sqrt(-1) * sqrt(16) * sqrt(5) = ±i * 4 * sqrt(5)Simplifying the expression: Simplify the expression by multiplying the real numbers. ±sqrt(-80) = ±4i * sqrt(5)

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Express the radical using the imaginary unit,
i.
Express your answer in simplified form.

+-sqrt(-80)=+-

Express the radical using the imaginary unit, $i$ . $\newline$ Express your answer in simplified form. $\newline$ $\pm \sqrt{-80}= \pm$

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Q. Express the radical using the imaginary unit,

i

\newline

Express your answer in simplified form.

\newline

\pm \sqrt{-80}= \pm

Expressing $\sqrt{-80}$ as a product: Express $\pm\sqrt{-80}$ as the product of square roots and $\sqrt{-1}$ .
$\pm\sqrt{-80} = \pm\sqrt{-1 \times 80}$
Factoring $80$ into $16 \times 5$ : Factor $80$ into $16 \times 5$ , since $16$ is a perfect square. $\newline$ $\pm\sqrt{-80} = \pm\sqrt{-1 \times 16 \times 5}$
Expressing $\sqrt{-1}$ as $\pm i$ : Express $\pm\sqrt{-1}$ as $\pm i$ and take the square root of $16$ .
$\pm\sqrt{-80} = \pm\sqrt{-1} \cdot \sqrt{16} \cdot \sqrt{5}$
= $\pm i \cdot 4 \cdot \sqrt{5}$
Simplifying the expression: Simplify the expression by multiplying the real numbers. $\pm\sqrt{-80} = \pm 4i \cdot \sqrt{5}$