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(8-i)-(-82+2i)=
Express your answer in the form 
(a+bi).

(8i)(82+2i)= (8-i)-(-82+2 i)= \newlineExpress your answer in the form (a+bi) (a+b i) .

Full solution

Q. (8i)(82+2i)= (8-i)-(-82+2 i)= \newlineExpress your answer in the form (a+bi) (a+b i) .
  1. Distribute negative sign: First, we need to distribute the negative sign to both terms in the second complex number, (82+2i)-(-82+2i). This means we will change the sign of both terms inside the parentheses.
  2. Subtract real parts: Now, we subtract the real parts and the imaginary parts separately. The real part of the first complex number is 88, and the real part of the second complex number is 82-82 (after distributing the negative sign). The imaginary part of the first complex number is i-i, and the imaginary part of the second complex number is 2i-2i (after distributing the negative sign).
  3. Subtract imaginary parts: Perform the subtraction for the real parts: 8(82)=8+82=908 - (-82) = 8 + 82 = 90.
  4. Combine results: Perform the subtraction for the imaginary parts: i(2i)=i+2i=i-i - (-2i) = -i + 2i = i.
  5. Combine results: Perform the subtraction for the imaginary parts: i(2i)=i+2i=i-i - (-2i) = -i + 2i = i. Combine the results of the real part and the imaginary part to express the answer in the form a+bia+bi: 90+i90 + i.

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