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noot: Additional Practice (LMS graded)\newlineof 22\newlinee surface area of a paper cup is defined by the function \newlines(h)=6π16+h2s(h)=6\pi\sqrt{16+h^{2}}, where \newlinehh is the height of the cup. What is the domain and range of \newlines(h)s(h) ?\newlineDescribe the domain. Select the correct choice below and, if necessary, fill in the answer box within your choice.\newlineA. The domain is \newline\{h\mid h>-\}.\newline(Type an inequality or a compound inequality. Simplify your answer. Type an exact answer, using \newlineπ\pi as needed.)\newlineB. The domain is all real numbers.

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Q. noot: Additional Practice (LMS graded)\newlineof 22\newlinee surface area of a paper cup is defined by the function \newlines(h)=6π16+h2s(h)=6\pi\sqrt{16+h^{2}}, where \newlinehh is the height of the cup. What is the domain and range of \newlines(h)s(h) ?\newlineDescribe the domain. Select the correct choice below and, if necessary, fill in the answer box within your choice.\newlineA. The domain is \newline{hh>}\{h\mid h>-\}.\newline(Type an inequality or a compound inequality. Simplify your answer. Type an exact answer, using \newlineπ\pi as needed.)\newlineB. The domain is all real numbers.
  1. Define Domain of Function: The domain of a function is the set of all possible input values (in this case, the height hh) that will produce a valid output (the surface area s(h)s(h)). Since the surface area cannot be negative and the square root function 16+h2\sqrt{16 + h^2} is defined for all real numbers (because the expression inside the square root is always positive), the domain of s(h)s(h) is all real numbers.
  2. Define Range of Function: The range of the function is the set of all possible output values. Since the square root function 16+h2\sqrt{16 + h^2} produces non-negative values and is multiplied by the positive constant 6π6\pi, the range of s(h)s(h) is all non-negative real numbers.

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