Moore's law says that the number of transistors in a dense integrated circuit increases by 41% every year. In 1974 , a dense integrated circuit was produced with 5000 transistors. Which expression gives the number of transistors in a dense integrated circuit in 1979? Choose 1 answer: (A) 5000*0.41^(5) (B) 5000+(1+0.41)^(5) (C) 5000(1+0.41)^(5) (D) 5000+0.41^(5)

Question

Moore's law says that the number of transistors in a dense integrated circuit increases by  41% every year. In 1974 , a dense integrated circuit was produced with 5000 transistors. Which expression gives the number of transistors in a dense integrated circuit in  1979? Choose 1 answer: (A)  5000*0.41^(5) (B)  5000+(1+0.41)^(5) (C)  5000(1+0.41)^(5) (D)  5000+0.41^(5)

Bytelearn · Accepted Answer

Understand Moore's Law: Understand Moore's Law in the context of the problem. Moore's Law suggests that the number of transistors on a dense integrated circuit doubles approximately every two years. However, in this problem, it is stated that the number of transistors increases by 41% every year. This means that each year, the number of transistors is 141% (or 1.41 times) of the previous year's number.Determine Initial Transistors: Determine the initial number of transistors and the number of years that have passed. The initial number of transistors in 1974 is given as 5000. The number of years from 1974 to 1979 is 5 years.Apply Percentage Increase: Apply the percentage increase to find the expression for the number of transistors in 1979. Since the number of transistors increases by 41% each year, we multiply the initial number by (1 + 0.41) for each year that has passed. This is equivalent to raising (1 + 0.41) to the power of the number of years, which is 5 in this case.Write Expression: Write the expression using the information from the previous steps. The expression for the number of transistors in 1979 is the initial number of transistors multiplied by (1 + 0.41) raised to the power of 5. This gives us: 5000 * (1 + 0.41)^5Match with Choices: Match the expression with the given choices. The correct expression that matches our calculation is: 5000 * (1.41)^5 This corresponds to choice (C) 5000(1+0.41)^(5).

Full solution

More problems from Divide numbers written in scientific notation

Related topics