Mathias was asked whether the following equation is an identity:2x2+10x+6=(x+3)(2x+1)+3(x+1)He performed the following steps:2x2+10x+6↪ Step 1=2x2+7x+3+(3x+3)↪ Step 2=2x2+6x+x+3+3(x+1)↪ Step 3=2x(x+3)+(x+3)+3(x+1)↪ Step 4=(x+3)(2x+1)+3(x+1)For this reason, Mathias stated that the equation is a true identity.Is Mathias correct? If not, in which step did he make a mistake?Choose 1 answer:(A) Mathias is correct.(B) Mathias is incorrect. He made a mistake in step 1.(C) Mathias is incorrect. He made a mistake in step 3.(D) Mathias is incorrect. He made a mistake in step 4.
Q. Mathias was asked whether the following equation is an identity:2x2+10x+6=(x+3)(2x+1)+3(x+1)He performed the following steps:2x2+10x+6↪ Step 1=2x2+7x+3+(3x+3)↪ Step 2=2x2+6x+x+3+3(x+1)↪ Step 3=2x(x+3)+(x+3)+3(x+1)↪ Step 4=(x+3)(2x+1)+3(x+1)For this reason, Mathias stated that the equation is a true identity.Is Mathias correct? If not, in which step did he make a mistake?Choose 1 answer:(A) Mathias is correct.(B) Mathias is incorrect. He made a mistake in step 1.(C) Mathias is incorrect. He made a mistake in step 3.(D) Mathias is incorrect. He made a mistake in step 4.
Check Mathias's step: Check Mathias's step 2.2x2+10x+6=2x2+6x+x+3+3(x+1)This simplifies to 2x2+7x+3+3x+3, which is not the original left-hand side.
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