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Mathias was asked whether the following equation is an identity:

2x^(2)+10 x+6=(x+3)(2x+1)+3(x+1)
He performed the following steps:

2x^(2)+10 x+6

harr^(" Step "1)=2x^(2)+7x+3+(3x+3)

longleftrightarrow^(" Step "2)=2x^(2)+6x+x+3+3(x+1)

harr^(" Step "3)=2x(x+3)+(x+3)+3(x+1)

longrightarrow^(" Step "4)=(x+3)(2x+1)+3(x+1)
For this reason, Mathias stated that the equation is a true identity.
Is Mathias correct? If not, in which step did he make a mistake?
Choose 1 answer:
(A) Mathias is correct.
(B) Mathias is incorrect. He made a mistake in step 1.
(C) Mathias is incorrect. He made a mistake in step 3.
(D) Mathias is incorrect. He made a mistake in step 4.

Mathias was asked whether the following equation is an identity:\newline2x2+10x+6=(x+3)(2x+1)+3(x+1) 2 x^{2}+10 x+6=(x+3)(2 x+1)+3(x+1) \newlineHe performed the following steps:\newline2x2+10x+6 2 x^{2}+10 x+6 \newline Step 1=2x2+7x+3+(3x+3) \stackrel{\text { Step } 1}{\hookrightarrow}=2 x^{2}+7 x+3+(3 x+3) \newline Step 2=2x2+6x+x+3+3(x+1) \stackrel{\text { Step } 2}{\hookrightarrow}=2 x^{2}+6 x+x+3+3(x+1) \newline Step 3=2x(x+3)+(x+3)+3(x+1) \stackrel{\text { Step } 3}{\hookrightarrow}=2 x(x+3)+(x+3)+3(x+1) \newline Step 4=(x+3)(2x+1)+3(x+1) \stackrel{\text { Step } 4}{\hookrightarrow}=(x+3)(2 x+1)+3(x+1) \newlineFor this reason, Mathias stated that the equation is a true identity.\newlineIs Mathias correct? If not, in which step did he make a mistake?\newlineChoose 11 answer:\newline(A) Mathias is correct.\newline(B) Mathias is incorrect. He made a mistake in step 11.\newline(C) Mathias is incorrect. He made a mistake in step 33.\newline(D) Mathias is incorrect. He made a mistake in step 44.

Full solution

Q. Mathias was asked whether the following equation is an identity:\newline2x2+10x+6=(x+3)(2x+1)+3(x+1) 2 x^{2}+10 x+6=(x+3)(2 x+1)+3(x+1) \newlineHe performed the following steps:\newline2x2+10x+6 2 x^{2}+10 x+6 \newline Step 1=2x2+7x+3+(3x+3) \stackrel{\text { Step } 1}{\hookrightarrow}=2 x^{2}+7 x+3+(3 x+3) \newline Step 2=2x2+6x+x+3+3(x+1) \stackrel{\text { Step } 2}{\hookrightarrow}=2 x^{2}+6 x+x+3+3(x+1) \newline Step 3=2x(x+3)+(x+3)+3(x+1) \stackrel{\text { Step } 3}{\hookrightarrow}=2 x(x+3)+(x+3)+3(x+1) \newline Step 4=(x+3)(2x+1)+3(x+1) \stackrel{\text { Step } 4}{\hookrightarrow}=(x+3)(2 x+1)+3(x+1) \newlineFor this reason, Mathias stated that the equation is a true identity.\newlineIs Mathias correct? If not, in which step did he make a mistake?\newlineChoose 11 answer:\newline(A) Mathias is correct.\newline(B) Mathias is incorrect. He made a mistake in step 11.\newline(C) Mathias is incorrect. He made a mistake in step 33.\newline(D) Mathias is incorrect. He made a mistake in step 44.
  1. Check Mathias's step: Check Mathias's step 22.2x2+10x+6=2x2+6x+x+3+3(x+1)2x^{2}+10x+6 = 2x^{2}+6x+x+3+3(x+1)This simplifies to 2x2+7x+3+3x+32x^{2}+7x+3+3x+3, which is not the original left-hand side.

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