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Let 
y=(x)/(sin(x)).

(dy)/(dx)=

Let y=xsin(x) y=\frac{x}{\sin (x)} .\newlinedydx= \frac{d y}{d x}=

Full solution

Q. Let y=xsin(x) y=\frac{x}{\sin (x)} .\newlinedydx= \frac{d y}{d x}=
  1. Identify Function and Rule: Identify the function that needs differentiation and the rule that should be applied. The function y=xsin(x)y = \frac{x}{\sin(x)} can be rewritten as y=xsin(x)1y = x \cdot \sin(x)^{-1}. To differentiate this function, we will use the product rule, which states that the derivative of a product of two functions is the derivative of the first function times the second function plus the first function times the derivative of the second function.
  2. Differentiate First Function: Differentiate the first function, which is xx. The derivative of xx with respect to xx is 11.
  3. Differentiate Second Function: Differentiate the second function, which is sin(x)1\sin(x)^{-1}. The derivative of sin(x)1\sin(x)^{-1} with respect to xx is cos(x)sin(x)2-\frac{\cos(x)}{\sin(x)^2}, which is derived using the chain rule and the derivative of sin(x)\sin(x), which is cos(x)\cos(x).
  4. Apply Product Rule: Apply the product rule. The derivative of yy with respect to xx is (1sin(x)1)+(x(cos(x)/sin(x)2))(1 \cdot \sin(x)^{-1}) + (x \cdot (-\cos(x)/\sin(x)^2)).
  5. Simplify Expression: Simplify the expression. The derivative of yy with respect to xx is sin(x)1xcos(x)sin(x)2\sin(x)^{-1} - \frac{x\cos(x)}{\sin(x)^2}.
  6. Combine Terms: Combine terms over a common denominator to further simplify the expression. The derivative of yy with respect to xx is 1xcos(x)sin(x)2\frac{1 - x\cos(x)}{\sin(x)^2}.

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