Q. Let y=ex.Find dxdy.Choose 1 answer:(A) xex−1(B) 2ex1(C) ex(D) 2ex
Write Function, Variable: Write down the function and identify the differentiation variable.We have the function y=ex. We want to find the derivative of y with respect to x, which is denoted as dxdy.
Apply Chain Rule: Apply the chain rule for differentiation.The chain rule states that the derivative of a composite function is the derivative of the outer function evaluated at the inner function times the derivative of the inner function. In this case, the outer function is the square root function, and the inner function is ex.
Differentiate Outer Function: Differentiate the outer function with respect to the inner function.The derivative of u with respect to u is 2u1, where u is the inner function. In this case, u=ex, so the derivative of the outer function is 2ex1.
Differentiate Inner Function: Differentiate the inner function with respect to x. The derivative of ex with respect to x is ex. So, the derivative of the inner function is ex.
Multiply Derivatives: Multiply the derivatives of the outer and inner functions.Using the chain rule from Step 2, we multiply the derivative of the outer function from Step 3 by the derivative of the inner function from Step 4. This gives us dxdy=2ex1×ex.
Simplify Expression: Simplify the expression.We can simplify the expression by canceling out one ex in the numerator with the ex in the denominator of the square root. This leaves us with dxdy=2exex.
Recognize Simplification: Recognize that ex/ex is the same as ex. Since ex is the same as (ex)2, we can simplify the expression further to get (dy)/(dx)=(ex)/(2).
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