Let y=f(x) be a differentiable function such that dxdy=yx and f(8)=2. What is the approximation of f(8.1) using the line tangent to the graph of f at x=8 ?
Q. Let y=f(x) be a differentiable function such that dxdy=yx and f(8)=2. What is the approximation of f(8.1) using the line tangent to the graph of f at x=8 ?
Identify derivative & point: Identify the derivative and the point of interest.Given that dxdy=yx and f(8)=2, we need to find the derivative at x=8.
Calculate derivative at x=8: Calculate the derivative at x=8.dxdy at x=8 is 28=4.
Use point-slope form: Use the point-slope form of the equation of a line to find the tangent line.The slope of the tangent line at x=8 is 4, and the point on the curve is (8,2).Equation of the tangent line: y−2=4(x−8).
Simplify tangent line equation: Simplify the equation of the tangent line. y−2=4x−32,y=4x−30.
Approximate f(8.1): Use the tangent line to approximate f(8.1).Substitute x=8.1 into the tangent line equation:y=4(8.1)−30,y=32.4−30,y=2.4.