Q. Let f be an exponential function of the form f(x)=abx. If f(0)=4 and f(3)=108, what is the equation of f ?
Given Exponential Function: We are given an exponential function f(x)=abx. To find the equation of f, we need to determine the values of a and b. We are given two points on the function: (0,4) and (3,108). We can use these points to create two equations.
Find Value of a: Using the point (0,4), we substitute x=0 and f(x)=4 into the equation f(x)=abx to find the value of a.f(0)=ab0=4Since any number raised to the power of 0 is 1, we have:a⋅1=4Therefore, a=4.
Find Value of b: Now we use the point (3,108) and our value for a to find b. We substitute x=3, f(x)=108, and a=4 into the equation f(x)=abx.f(3)=4b3=108To find b, we divide both sides by (3,108)0:(3,108)1(3,108)2
Calculate Final Equation: To find the value of b, we take the cube root of both sides of the equation b3=27.b=2731b=3
Calculate Final Equation: To find the value of b, we take the cube root of both sides of the equation b3=27. b=2731 b=3Now that we have both a and b, we can write the equation of the exponential function f. f(x)=abx f(x)=4×3x This is the equation of the function f.