For the function f(x)=8x^(2)-2x+11, find the slope of the tangent line at x=11. Answer:

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For the function  f(x)=8x^(2)-2x+11, find the slope of the tangent line at  x=11. Answer:

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Calculate Derivative: To find the slope of the tangent line at a specific point on the graph of a function, we need to calculate the derivative of the function. The derivative of a function at a given point gives us the slope of the tangent line at that point.Apply Power Rule: The function given is f(x) = 8x^2 - 2x + 11. We will find the derivative of this function, f'(x), using the power rule. The power rule states that the derivative of x^n is n*x^(n-1).Evaluate Derivative at x=11: Applying the power rule to each term of the function: The derivative of 8x^2 is 16x (since 2*8x^(2-1) = 16x). The derivative of -2x is -2 (since 1*-2x^(1-1) = -2). The derivative of a constant, like 11, is 0. So, the derivative of the function f(x) is f'(x) = 16x - 2.Calculate f'(11): Now we need to evaluate the derivative at x = 11 to find the slope of the tangent line at that point. f'(11) = 16*11 - 2.Find Slope at x=11: Calculate the value of f'(11): f'(11) = 16*11 - 2 = 176 - 2 = 174.Final Answer: The slope of the tangent line at x = 11 is 174. This is the final answer.

For the function $f(x)=8 x^{2}-2 x+11$ , find the slope of the tangent line at $x=11$ . $\newline$ Answer:

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For the function f(x)=8x2−2x+11 f(x)=8 x^{2}-2 x+11 f(x)=8x2−2x+11, find the slope of the tangent line at x=11 x=11 x=11.\newlineAnswer:

For the function $f(x)=8 x^{2}-2 x+11$ , find the slope of the tangent line at $x=11$ . $\newline$ Answer: