Let h be a continuous function on the closed interval [−3,4], where h(−3)=−1 and h(4)=2.Which of the following is guaranteed by the Intermediate Value Theorem?Choose 1 answer:(A) h(c)=1 for at least one c between −1 and 2(B) h(c)=1 for at least one c between −3 and 4(C) h(c)=−2 for at least one c between −3 and 4(D) h(c)=−2 for at least one c between −1 and 2
Q. Let h be a continuous function on the closed interval [−3,4], where h(−3)=−1 and h(4)=2.Which of the following is guaranteed by the Intermediate Value Theorem?Choose 1 answer:(A) h(c)=1 for at least one c between −1 and 2(B) h(c)=1 for at least one c between −3 and 4(C) h(c)=−2 for at least one c between −3 and 4(D) h(c)=−2 for at least one c between −1 and 2
Understand IVT: Understand the Intermediate Value Theorem (IVT). The Intermediate Value Theorem states that if a function f is continuous on a closed interval [a,b] and k is any number between f(a) and f(b), then there exists at least one c in the interval [a,b] such that f(c)=k.
Apply to function h: Apply the IVT to the given function h. We are given that h is continuous on the closed interval [−3,4], h(−3)=−1, and h(4)=2. We need to find if there is a value c in the interval [−3,4] such that h(c) equals a certain value.
Evaluate based on IVT: Evaluate the choices based on the IVT.(A) h(c)=1 for at least one c between −1 and 2. This choice is not relevant because the interval [−1,2] is not the interval we are considering for the function h.
Continue evaluating choices: Continue evaluating the choices.(B) h(c)=1 for at least one c between −3 and 4. Since 1 is between h(−3)=−1 and h(4)=2, and the function h is continuous on [−3,4], the IVT guarantees that there is at least one c in the interval [−3,4] where h(c)=1.
Evaluate remaining choices: Evaluate the remaining choices.(C) h(c)=−2 for at least one c between −3 and 4. Since −2 is not between h(−3)=−1 and h(4)=2, the IVT does not guarantee that there is a c where h(c)=−2 in the interval [−3,4].
Evaluate last choice: Evaluate the last choice.(D) h(c)=−2 for at least one c between −1 and 2. This choice is also not relevant because the interval [−1,2] is not the interval we are considering for the function h, and −2 is not between h(−3)=−1 and h(4)=2.
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