Q. Let g(x)=exsin(x).Find g′(x).Choose 1 answer:(A) cos(x)−ex(B) ex(cos(x)−sin(x))(C) excos(x)(D) excos(x)−sin(x)
Apply Quotient Rule: Apply the quotient rule to find the derivative of g(x)=exsin(x). The quotient rule states that if you have a function h(x)=g(x)f(x), then h′(x)=(g(x))2f′(x)g(x)−f(x)g′(x). Here, f(x)=sin(x) and g(x)=ex.
Find f′(x): Find the derivative of f(x)=sin(x), which is f′(x)=cos(x).
Find g′(x): Find the derivative of g(x)=ex, which is g′(x)=ex.
Apply Quotient Rule: Apply the quotient rule using the derivatives from steps 2 and 3.g′(x)=(ex)2cos(x)ex−sin(x)ex.
Simplify Expression: Simplify the expression by factoring out ex from the numerator and canceling one ex from the numerator and denominator.g′(x)=exexex(cos(x)−sin(x)).g′(x)=excos(x)−sin(x).
Match Correct Answer: Match the simplified derivative with the given answer choices.The correct answer is (D) (cos(x)−sin(x))/(ex).
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