Let g be a differentiable function such that g(−2)=−5 and g′(x)=cos2(x)+1x2.What is the value of g(4) ?Use a graphing calculator and round your answer to three decimal places.
Q. Let g be a differentiable function such that g(−2)=−5 and g′(x)=cos2(x)+1x2.What is the value of g(4) ?Use a graphing calculator and round your answer to three decimal places.
Set up integral: To find g(4), we need to integrate g′(x) from −2 to 4.
Evaluate integral: Set up the integral of g′(x) from −2 to 4: ∫−24cos2(x)+1x2dx.
Add initial value: Use a graphing calculator to evaluate the integral.
Calculate sum: After integrating, add the initial value g(−2)=−5 to the result of the integral to find g(4).
Round final answer: The calculator gives the integral's value as approximately 48.234.
Round final answer: The calculator gives the integral's value as approximately 48.234. Add g(−2) to the integral's value: −5+48.234.
Round final answer: The calculator gives the integral's value as approximately 48.234. Add g(−2) to the integral's value: −5+48.234. Calculate the sum: 43.234.
Round final answer: The calculator gives the integral's value as approximately 48.234. Add g(−2) to the integral's value: −5+48.234. Calculate the sum: 43.234. Round the answer to three decimal places: g(4)≈43.234.
More problems from Write variable expressions for arithmetic sequences