Let f be a twice differentiable function, and let f(3)=8, f′(3)=0, and f′′(3)=0.What occurs in the graph of f at the point (3,8) ?Choose 1 answer:(A) (3,8) is a minimum point.(B) (3,8) is a maximum point.(C) There's not enough information to tell.
Q. Let f be a twice differentiable function, and let f(3)=8, f′(3)=0, and f′′(3)=0.What occurs in the graph of f at the point (3,8) ?Choose 1 answer:(A) (3,8) is a minimum point.(B) (3,8) is a maximum point.(C) There's not enough information to tell.
Given Information: To determine what occurs at the point (3,8), we need to analyze the given information about the function f and its derivatives at x=3.Given:f(3)=8, which means the point (3,8) lies on the graph of f.f′(3)=0, which indicates that the slope of the tangent to the graph of f at x=3 is zero. This could mean that (3,8) is a maximum, a minimum, or a point of inflection.f0, which means the concavity of the graph at x=3 is neither upwards nor downwards. This does not provide conclusive information about whether (3,8) is a maximum or minimum point.
Analysis of f′(x): To determine if (3,8) is a maximum or minimum point, we would need the sign of the second derivative around x=3. Since f′′(3)=0, we cannot conclude whether the graph is concave up or concave down at this point. If f′′(x) were positive for x near 3, it would indicate a minimum point. If f′′(x) were negative for x near 3, it would indicate a maximum point. However, with f′′(3)=0, we cannot make this determination.
Determining Maximum or Minimum: Since we do not have information about the behavior of f′′(x) around x=3 other than at the exact point x=3, we cannot determine if (3,8) is a maximum or minimum point. We need additional information about the concavity of f near x=3 to make a definitive conclusion.
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