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Jen was asked to determine whether 
f(x)=(1)/(root(3)(x)) is even, odd, or neither. Here is her work:
Step 1: Find expression for 
f(-x)

{:[f(-x)=(1)/(root(3)((-x)))],[=(1)/(root(3)(-1)*root(3)(x))],[=-(1)/(root(3)(x))]:}
Step 2: Check if 
f(-x) is equal to 
f(x) or 
-f(x)

-(1)/(root(3)(x)) is the same as

-f(x)=-(1)/(root(3)(x)).
Step 3: Conclusion

f(-x) is equivalent to 
-f(x), so 
f is even.
Is Jen's work correct? If not, what is the first step where Jen made a mistake?
Choose 1 answer:
(A) Jen's work is correct.
(B) Jen's work is incorrect. She first made a mistake in Step 1.
(C) Jen's work is incorrect. She first made a mistake in Step 2.
(D) Jen's work is incorrect. She first made a mistake in Step 3.

Jen was asked to determine whether f(x)=1x3 f(x)=\frac{1}{\sqrt[3]{x}} is even, odd, or neither. Here is her work:\newlineStep 11: Find expression for f(x) f(-x) \newlinef(x)amp;=1(x)3amp;=113x3amp;=1x3 \begin{aligned} f(-x) & =\frac{1}{\sqrt[3]{(-x)}} \\ & =\frac{1}{\sqrt[3]{-1} \cdot \sqrt[3]{x}} \\ & =-\frac{1}{\sqrt[3]{x}} \end{aligned} \newlineStep 22: Check if f(x) f(-x) is equal to f(x) f(x) or f(x) -f(x) \newline1x3 -\frac{1}{\sqrt[3]{x}} is the same as\newlinef(x)=1x3. -f(x)=-\frac{1}{\sqrt[3]{x}} . \newlineStep 33: Conclusion\newlinef(x) f(-x) is equivalent to f(x) -f(x) , so f f is even.\newlineIs Jen's work correct? If not, what is the first step where Jen made a mistake?\newlineChoose 11 answer:\newline(A) Jen's work is correct.\newline(B) Jen's work is incorrect. She first made a mistake in Step 11.\newline(C) Jen's work is incorrect. She first made a mistake in Step 22.\newline(D) Jen's work is incorrect. She first made a mistake in Step 33.

Full solution

Q. Jen was asked to determine whether f(x)=1x3 f(x)=\frac{1}{\sqrt[3]{x}} is even, odd, or neither. Here is her work:\newlineStep 11: Find expression for f(x) f(-x) \newlinef(x)=1(x)3=113x3=1x3 \begin{aligned} f(-x) & =\frac{1}{\sqrt[3]{(-x)}} \\ & =\frac{1}{\sqrt[3]{-1} \cdot \sqrt[3]{x}} \\ & =-\frac{1}{\sqrt[3]{x}} \end{aligned} \newlineStep 22: Check if f(x) f(-x) is equal to f(x) f(x) or f(x) -f(x) \newline1x3 -\frac{1}{\sqrt[3]{x}} is the same as\newlinef(x)=1x3. -f(x)=-\frac{1}{\sqrt[3]{x}} . \newlineStep 33: Conclusion\newlinef(x) f(-x) is equivalent to f(x) -f(x) , so f f is even.\newlineIs Jen's work correct? If not, what is the first step where Jen made a mistake?\newlineChoose 11 answer:\newline(A) Jen's work is correct.\newline(B) Jen's work is incorrect. She first made a mistake in Step 11.\newline(C) Jen's work is incorrect. She first made a mistake in Step 22.\newline(D) Jen's work is incorrect. She first made a mistake in Step 33.
  1. Find f(x)f(-x): Find expression for f(x)f(-x).\newlinef(x)=1x3f(-x) = \frac{1}{\sqrt[3]{-x}}
  2. Check function symmetry: Check if f(x)f(-x) is equal to f(x)f(x) or f(x)-f(x).\newlineSince f(x)=1x3f(-x) = -\frac{1}{\sqrt[3]{x}}, this is the same as f(x)=1x3-f(x) = -\frac{1}{\sqrt[3]{x}}.
  3. Conclusion: Conclusion.\newlineJen concluded that f(x)f(-x) is equivalent to f(x)-f(x), so ff is even. However, this is incorrect because if f(x)=f(x)f(-x) = -f(x), the function is odd, not even.

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