In a direct variation, y = 15 when x = 5. Write a direct variation equation that shows the relationship between x and y. Write your answer as an equation with y first, followed by an equals sign. ____

Identify Form: Identify the form of the direct variation equation. Direct variation can be represented by the equation y = kx, where k is the constant of variation.Find Constant: Use the given values to find the constant of variation (k). We are given that y = 15 when x = 5. We can substitute these values into the direct variation equation to find k. 15 = k * 5Solve for k: Solve for k. To find k, we divide both sides of the equation by 5. k = 15 / 5 k = 3Write Equation: Write the direct variation equation using the value of k. Now that we have found k to be 3, we can write the direct variation equation as y = kx. Substituting k = 3 into the equation gives us y = 3x.

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In a direct variation, $y = 15$ when $x = 5$ . Write a direct variation equation that shows the relationship between $x$ and $y$ . $\newline$ Write your answer as an equation with $y$ first, followed by an equals sign.

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Algebra 1

Write direct variation equations

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Q. In a direct variation,

y = 15

when

x = 5

. Write a direct variation equation that shows the relationship between

x

and

y

\newline

Write your answer as an equation with

y

first, followed by an equals sign.

Identify Form: Identify the form of the direct variation equation. $\newline$ Direct variation can be represented by the equation $y = kx$ , where $k$ is the constant of variation.
Find Constant: Use the given values to find the constant of variation $k$ . We are given that $y = 15$ when $x = 5$ . We can substitute these values into the direct variation equation to find $k$ . $15 = k \times 5$
Solve for k: Solve for k. $\newline$ To find k, we divide both sides of the equation by $5$ . $\newline$ $k = \frac{15}{5}$ $\newline$ $k = 3$
Write Equation: Write the direct variation equation using the value of $k$ . Now that we have found $k$ to be $3$ , we can write the direct variation equation as $y = kx$ . Substituting $k = 3$ into the equation gives us $y = 3x$ .