(x+4)(2x-a)=0 In the given equation, a is a constant. If the equation has the solutions x=4 and x=-4, what is the value of a ?

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(x+4)(2x-a)=0 In the given equation,  a is a constant. If the equation has the solutions  x=4 and  x=-4, what is the value of  a ?

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Identify Solutions: Identify the solutions of the equation. The given equation is in factored form, which means that the solutions for x are the values that make each factor equal to zero. According to the problem, the solutions are x=4 and x=-4.Apply First Solution: Apply the first solution to the equation. If x=4 is a solution, then substituting x=4 into the equation (x+4)(2x-a)=0 should result in a true statement. Let's substitute x=4 into the equation and see what we get. (4+4)(2*4-a)=0 (8)(8-a)=0Solve for a: Solve for a using the first solution. Since (8)(8-a)=0, we know that one of the factors must be zero. The first factor, 8, is not zero, so the second factor, 8-a, must be zero. Therefore, we can set 8-a=0 and solve for a. 8-a=0 a=8Verify with Second Solution: Verify the solution with the second solution. Now we need to check if a=8 works for the second solution x=-4. Substitute x=-4 into the equation (x+4)(2x-a)=0 with a=8. (-4+4)(2*(-4)-8)=0 (0)(-8-8)=0 (0)(-16)=0Confirm Correct Value: Confirm that the value of a is correct. Since the second factor is zero when x=-4, the equation is satisfied. This confirms that a=8 is the correct value for a, as it works for both solutions x=4 and x=-4.

$(x+4)(2 x-a)=0$ $\newline$ In the given equation, $a$ is a constant. If the equation has the solutions $x=4$ and $x=-4$ , what is the value of $a$ ?

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(x+4)(2x−a)=0 (x+4)(2 x-a)=0 (x+4)(2x−a)=0\newlineIn the given equation, a a a is a constant. If the equation has the solutions x=4 x=4 x=4 and x=−4 x=-4 x=−4, what is the value of a a a ?

$(x+4)(2 x-a)=0$ $\newline$ In the given equation, $a$ is a constant. If the equation has the solutions $x=4$ and $x=-4$ , what is the value of $a$ ?