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What is the value of
(x^(2))/(y^(4)) when
x=8 and
y=2 ?

What is the value of $\frac{x^{2}}{y^{4}}$ when $x=8$ and $y=2$ ?

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Write and solve direct variation equations

Full solution

Q. What is the value of

\frac{x^{2}}{y^{4}}

when

x=8

and

y=2

?

Given Values: We are given: $\newline$ $x = 8$ $\newline$ $y = 2$ $\newline$ Expression = $\frac{x^{2}}{y^{4}}$ $\newline$ Identify the expression after substituting the value of $x$ and $y$ . $\newline$ Substitute $8$ for $x$ and $2$ for $y$ in $\frac{x^{2}}{y^{4}}$ . $\newline$ $y = 2$ $0$
Substitute Values: Calculate the value of $x$ squared, which is $8$ squared. $8^{2} = 8 \times 8 = 64$
Calculate $x^2$ : Calculate the value of $y$ to the power of $4$ , which is $2$ to the power of $4$ . $2^{4} = 2 \times 2 \times 2 \times 2 = 16$
Calculate $y$ to the power of $4$ : Divide $x$ squared by $y$ to the power of $4$ . $\frac{64}{16}$ $= 4$

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