How does h(t)=-2t-1 change over the interval from t=-5 to t=-2 ?\n\nh(t) decreases by a factor of 6\n\nh(t) decreases by 6\n\nh(t) decreases by 8\n\nh(t) decreases by 4

Step 1: Find h(-5): We have: h(t) = -2t - 1 Find the value of h(-5). Substitute t = -5 in h(t) = -2t - 1. h(-5) = -2(-5) - 1 h(-5) = 10 - 1 h(-5) = 9Step 2: Find h(-2): Step 2: We have: h(t) = -2t - 1 Find the value of h(-2). Substitute t = -2 in h(t) = -2t - 1. h(-2) = -2(-2) - 1 h(-2) = 4 - 1 h(-2) = 3Step 3: Subtract h(-5) from h(-2): Step 3: We found: h(-5) = 9 h(-2) = 3 Subtract h(-5) from h(-2). h(-2) - h(-5) = 3 - 9 = -6Step 4: Analyze h(t) Behavior: Step 4: Change: h(-2) - h(-5) = -6 Is h(t) increases, decreases, or remains unchanged? The value of h(t) reduces from 9 to 3. So, h(t) decreases.Step 5: Analyze Change in h(t): Step 5: We found: Change: -6 Behavior of h(t): decreases How does h(t) = -2t - 1 change from t = -5 to t = -2? We found that h(t) decreases and the difference is -6. h(t) decreases by 6.

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How does $h(t)=-2t-1$ change over the interval from $t=-5$ to $t=-2$ ? $\newline$ $h(t)$ decreases by a factor of $6$ $\newline$ $h(t)$ decreases by $6$ $\newline$ $h(t)$ decreases by $8$ $\newline$ $h(t)$ decreases by $4$

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Q. How does

h(t)=-2t-1

change over the interval from

t=-5

t=-2

\newline

h(t)

decreases by a factor of

6

\newline

h(t)

decreases by

6

\newline

h(t)

decreases by

8

\newline

h(t)

decreases by

4

Step $1$ : Find $h(-5)$ : $\newline$ We have: $h(t) = -2t - 1$ $\newline$ Find the value of $h(-5)$ . $\newline$ Substitute $t = -5$ in $h(t) = -2t - 1$ . $\newline$ $h(-5) = -2(-5) - 1$ $\newline$ $h(-5) = 10 - 1$ $\newline$ $h(-5) = 9$
Step $2$ : Find $h(-2)$ : $\newline$ We have: $h(t) = -2t - 1$ $\newline$ Find the value of $h(-2)$ . $\newline$ Substitute $t = -2$ in $h(t) = -2t - 1$ . $\newline$ $h(-2) = -2(-2) - 1$ $\newline$ $h(-2) = 4 - 1$ $\newline$ $h(-2) = 3$
Step $3$ : Subtract $h(-5)$ from $h(-2)$ : We found: $h(-5) = 9$ and $h(-2) = 3$ $\newline$ Subtract $h(-5)$ from $h(-2)$ . $\newline$ $h(-2) - h(-5) = 3 - 9 = -6$
Step $4$ : Analyze h(t) Behavior: Change: $h(-2) - h(-5) = -6$ $\newline$ Is $h(t)$ increases, decreases, or remains unchanged? $\newline$ The value of $h(t)$ reduces from $9$ to $3$ . So, $h(t)$ decreases.
Step $5$ : Analyze Change in $h(t)$ : We found: Change: $-6$ Behavior of $h(t)$ : decreases $\newline$ How does $h(t) = -2t - 1$ change from $t = -5$ to $t = -2$ ? We found that $h(t)$ decreases and the difference is $-6$ . $\newline$ $h(t)$ decreases by $6$ .