h(t)=−4.9t2+9.8t+39.2Kaia throws a stone vertically upward from a bridge. The height, in meters, of the stone above the water t seconds after the throw can be modeled by the quadratic function given. How many seconds after the throw does the stone hit the water?Choose 1 answer:(A) 1(B) 2(C) 4(D) 8
Q. h(t)=−4.9t2+9.8t+39.2Kaia throws a stone vertically upward from a bridge. The height, in meters, of the stone above the water t seconds after the throw can be modeled by the quadratic function given. How many seconds after the throw does the stone hit the water?Choose 1 answer:(A) 1(B) 2(C) 4(D) 8
Find when stone hits water: To find when the stone hits the water, we need to find when h(t)=0.
Set equation to 0: Set the equation to 0 and solve for t: −4.9t2+9.8t+39.2=0.
Divide and simplify: Divide the entire equation by −4.9 to simplify: t2−2t−8=0.