Q. Answer the following True or False.Since dxd3x31=x−32, the fundamental theorem of calculus tells us that ∫−11x−32dx=3(131)−3(−1)31=6.TrueFalse
Verify Derivative: Let's first verify the derivative given in the statement.Given the function f(x)=3x31, we need to find its derivative f′(x).Using the power rule for derivatives, we have:f′(x)=dxd[3x31]=3⋅(31)⋅x(31−1)=x−32.
Apply Fundamental Theorem: Now, let's apply the Fundamental Theorem of Calculus, which states that if F is an antiderivative of f on an interval [a,b], then:∫abf(x)dx=F(b)−F(a).Here, f(x)=x(−2/3) and F(x)=3x(1/3) is its antiderivative.
Evaluate Integral: We will now evaluate the integral using the antiderivative: ∫−11x−32dx=F(1)−F(−1)=3(131)−3((−1)31).
Be Careful with Evaluation: We need to be careful with the evaluation of F(−1) because (−1)31 is not equal to −1. The cube root of −1 is −1, so we have: F(1)−F(−1)=3(1)−3(−1)=3+3=6.
Statement Verification: The statement given is "Since (dxd3x(31)=x−(32)), the fundamental theorem of calculus tells us that ∫−11x−(32)dx=3(1(31))−3(−1)(31)=6." Based on our calculations, this statement is true.