Consider this matrix transformation: [[-3,4],[-3,2]] What is the image of [[-2],[2]] under this transformation?

Matrix Multiplication: To find the image of the vector [[-2],[2]] under the transformation defined by the matrix [[-3,4],[-3,2]], we need to perform matrix multiplication.First Element Calculation: The multiplication process involves taking the dot product of each row of the matrix with the vector. For the first element of the resulting vector, we multiply the first row of the matrix by the vector: (-3 * -2) + (4 * 2) = 6 + 8 = 14Second Element Calculation: For the second element of the resulting vector, we multiply the second row of the matrix by the vector: (-3 * -2) + (2 * 2) = 6 + 4 = 10Combining Results: Combining the results from the two steps above, we get the image of the vector [[-2],[2]] under the transformation as: [[14],[10]]

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Consider this matrix transformation:

[[-3,4],[-3,2]]
What is the image of
[[-2],[2]] under this transformation?

Consider this matrix transformation: $\newline$ $\left[\begin{array}{ll} -3 & 4 \\ & \\ -3 & 2 \end{array}\right]$ $\newline$ What is the image of $\left[\begin{array}{c}-2 \\ 2\end{array}\right]$ under this transformation?

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Q. Consider this matrix transformation:

\newline

\left[\begin{array}{ll} -3 & 4 \\ & \\ -3 & 2 \end{array}\right]

\newline

What is the image of

\left[\begin{array}{c}-2 \\ 2\end{array}\right]

under this transformation?

Matrix Multiplication: To find the image of the vector \begin{bmatrix}-2\2\end{bmatrix} under the transformation defined by the matrix \begin{bmatrix}-3 & 4\-3 & 2\end{bmatrix}, we need to perform matrix multiplication.
First Element Calculation: The multiplication process involves taking the dot product of each row of the matrix with the vector. For the first element of the resulting vector, we multiply the first row of the matrix by the vector: $\newline$ $(-3 \times -2) + (4 \times 2) = 6 + 8 = 14$
Second Element Calculation: For the second element of the resulting vector, we multiply the second row of the matrix by the vector: $\newline$ $(-3 \times -2) + (2 \times 2) = 6 + 4 = 10$
Combining Results: Combining the results from the two steps above, we get the image of the vector \begin{bmatrix}-2\2\end{bmatrix} under the transformation as: \begin{bmatrix}14\10\end{bmatrix}