Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Given the substitutions 
ln 2=a,ln 3=b, and 
ln 5=c, find the value of 
ln(10) in terms of 
a,b, and 
c.
Answer:

Given the substitutions ln2=a,ln3=b \ln 2=a, \ln 3=b , and ln5=c \ln 5=c , find the value of ln(10) \ln (10) in terms of a,b a, b , and c c .\newlineAnswer:

Full solution

Q. Given the substitutions ln2=a,ln3=b \ln 2=a, \ln 3=b , and ln5=c \ln 5=c , find the value of ln(10) \ln (10) in terms of a,b a, b , and c c .\newlineAnswer:
  1. Factorization of ln(10)\ln(10): We know that ln(10)\ln(10) can be expressed as the sum of the natural logarithms of its prime factors, which are 22 and 55. So, ln(10)=ln(2×5)\ln(10) = \ln(2 \times 5). Using the property of logarithms that ln(xy)=ln(x)+ln(y)\ln(xy) = \ln(x) + \ln(y), we can write ln(10)\ln(10) as ln(2)+ln(5)\ln(2) + \ln(5).
  2. Substitution of ln(2)\ln(2) and ln(5)\ln(5): Given that ln2=a\ln 2 = a and ln5=c\ln 5 = c, we can substitute these values into our expression for ln(10)\ln(10). So, ln(10)=a+c\ln(10) = a + c.
  3. Final expression for ln(10)\ln(10): We have now expressed ln(10)\ln(10) in terms of aa and cc. Since there is no bb in the expression, we do not need to include ln3\ln 3 in our final answer.

More problems from Write and solve inverse variation equations