Q. Given the substitutions ln2=a,ln3=b, and ln5=c, find the value of ln(10) in terms of a,b, and c.Answer:
Factorization of ln(10): We know that ln(10) can be expressed as the sum of the natural logarithms of its prime factors, which are 2 and 5. So, ln(10)=ln(2×5). Using the property of logarithms that ln(xy)=ln(x)+ln(y), we can write ln(10) as ln(2)+ln(5).
Substitution of ln(2) and ln(5): Given that ln2=a and ln5=c, we can substitute these values into our expression for ln(10). So, ln(10)=a+c.
Final expression for ln(10): We have now expressed ln(10) in terms of a and c. Since there is no b in the expression, we do not need to include ln3 in our final answer.
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