Q. Given that f(x)=x+4,g(x)=4x and h(x)=2f(x−1)+3g(x), then what is the value of h(1) ?Answer:
Given Functions: Given the functions f(x)=x+4, g(x)=4x, and h(x)=2f(x−1)+3g(x), we need to find the value of h(1). Let's start by finding the value of f(x−1) and g(x) when x=1.
Calculate f(0): First, we calculate f(1−1) which is f(0). Using the definition of f(x), we have f(0)=0+4=4.
Calculate g(1): Next, we calculate g(1) using the definition of g(x). We have g(1)=4×1=4.
Substitute into h(1): Now we have both f(0) and g(1), we can substitute these values into the definition of h(x) to find h(1). So, h(1)=2f(1−1)+3g(1)=2f(0)+3g(1).
Final Calculation: Substitute the values we found into the equation for h(1): h(1)=2×4+3×4=8+12=20.
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