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Given that
f(x)=5x,quad g(x)=x+1 and
h(x)=f(x+1)-2g(x-2), then what is the value of
h(1) ?
Answer:

Given that $f(x)=5 x, \quad g(x)=x+1$ and $h(x)=f(x+1)-2 g(x-2)$ , then what is the value of $h(1)$ ? $\newline$ Answer:

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Write and solve inverse variation equations

Full solution

Q. Given that

f(x)=5 x, \quad g(x)=x+1

and

h(x)=f(x+1)-2 g(x-2)

, then what is the value of

h(1)

?

\newline

Answer:

Understand Given Functions: Understand the functions given and what is asked. $\newline$ We are given three functions: $f(x) = 5x$ , $g(x) = x + 1$ , and $h(x) = f(x + 1) - 2g(x - 2)$ . We need to find the value of $h(1)$ .
Calculate $f(x + 1)$ : Calculate $f(x + 1)$ when $x = 1$ . $\newline$ Substitute $x = 1$ into the function $f(x) = 5x$ to get $f(1 + 1)$ . $\newline$ $f(1 + 1) = 5(1 + 1) = 5(2) = 10$
Calculate $g(x - 2)$ : Calculate $g(x - 2)$ when $x = 1$ . $\newline$ Substitute $x = 1$ into the function $g(x) = x + 1$ to get $g(1 - 2)$ . $\newline$ $g(1 - 2) = (1 - 2) + 1 = -1 + 1 = 0$
Calculate $h(1)$ : Calculate $h(1)$ using the values from Step $2$ and Step $3$ . $\newline$ Substitute the results into $h(x) = f(x + 1) - 2g(x - 2)$ to find $h(1)$ . $\newline$ $h(1) = f(1 + 1) - 2g(1 - 2) = 10 - 2(0) = 10 - 0 = 10$

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