Q. Given that f(x)=4x,g(x)=x+5 and h(x)=−2f(x−2)−2g(x+3), then what is the value of h(2) ?Answer:
Given functions and task: Given the functions f(x)=4x, g(x)=x+5, and h(x)=−2f(x−2)−2g(x+3), we need to find the value of h(2). First, we will find the value of f(x−2) and g(x+3) when x=2.
Calculate f(x−2): Calculate f(x−2) when x=2.f(x−2)=4(x−2)=4(2−2)=4(0)=0.
Calculate g(x+3): Calculate g(x+3) when x=2. g(x+3)=(x+3)+5=(2+3)+5=5+5=10.
Substitute values into h(x): Now, we will substitute these values into the equation for h(x).h(x)=−2f(x−2)−2g(x+3).Substitute f(2−2)=0 and g(2+3)=10 into the equation.h(2)=−2(0)−2(10)=0−20=−20.
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