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g(w)=(w+13)^(3)(w+19)^(2)
The polynomial function 
g is defined. When 
g(w) is divided by 
(w+16), the remainder is 
r. What is the value of 
|r| ?

g(w)=(w+13)3(w+19)2 g(w)=(w+13)^{3}(w+19)^{2} \newlineThe polynomial function g g is defined. When g(w) g(w) is divided by (w+16) (w+16) , the remainder is r r . What is the value of r |r| ?

Full solution

Q. g(w)=(w+13)3(w+19)2 g(w)=(w+13)^{3}(w+19)^{2} \newlineThe polynomial function g g is defined. When g(w) g(w) is divided by (w+16) (w+16) , the remainder is r r . What is the value of r |r| ?
  1. Use Remainder Theorem: To find the remainder when g(w)g(w) is divided by (w+16)(w+16), we can use the Remainder Theorem. The Remainder Theorem states that if a polynomial f(x)f(x) is divided by (xc)(x - c), the remainder is f(c)f(c). In this case, we need to evaluate g(16)g(-16).
  2. Substitute w=16w = -16: Let's substitute w=16w = -16 into the function g(w)g(w) to find the remainder rr.\newlineg(w)=(w+13)3(w+19)2g(w) = (w+13)^{3}(w+19)^{2}\newliner=g(16)=((16)+13)3((16)+19)2r = g(-16) = ((-16)+13)^{3}((-16)+19)^{2}
  3. Calculate values: Now we calculate the values inside the parentheses. r=(3)3(3)2r = (-3)^{3}(3)^{2}
  4. Calculate powers: Next, we calculate the powers. r=(27)(9)r = (-27)(9)
  5. Multiply numbers: Now we multiply the two numbers to find the remainder rr.\newliner=27×9r = -27 \times 9\newliner=243r = -243
  6. Find absolute value: The question asks for the absolute value of rr, which is r|r|.\newliner=243|r| = |-243|
  7. Calculate absolute value: Finally, we calculate the absolute value of 243-243.r=243|r| = 243

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