g(n)=-11*4^(n) Complete the recursive formula of g(n). g(1)=_____ g(n)=g(n-1) . _____

Find Initial Value: To find the initial value g(1), we substitute n with 1 in the function g(n)=-11*4^(n). Calculation: g(1) = -11*4^(1) = -11*4 = -44Recursive Formula: The recursive formula for g(n) is based on the relationship between g(n) and g(n-1). Since g(n)=-11*4^(n), we can express g(n) in terms of g(n-1) by recognizing that 4^(n) = 4*4^(n-1). Therefore, g(n) = -11*4*4^(n-1). Since g(n-1) = -11*4^(n-1), we can write g(n) as 4 times g(n-1). Calculation: g(n) = 4*g(n-1)

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g(n)=-11*4^(n)
Complete the recursive formula of g(n).
g(1)=_____
g(n)=g(n-1) . _____

$g(n)=-11 \cdot 4^{n}$ $\newline$ Complete the recursive formula of $g(n)$ . $\newline$ $g(1)=\_\_\_\_\_$ $\newline$ $g(n)=g(n-1) \text {. } \_\_\_\_\_$

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g(n)=-11 \cdot 4^{n}

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Complete the recursive formula of

g(n)

\newline

g(1)=\_\_\_\_\_

\newline

g(n)=g(n-1) \text {. } \_\_\_\_\_

Find Initial Value: To find the initial value $g(1)$ , we substitute $n$ with $1$ in the function $g(n)=-11\cdot4^{(n)}$ . $\newline$ Calculation: $g(1) = -11\cdot4^{(1)} = -11\cdot4 = -44$
Recursive Formula: The recursive formula for $g(n)$ is based on the relationship between $g(n)$ and $g(n-1)$ . Since $g(n)=-11\cdot4^{n}$ , we can express $g(n)$ in terms of $g(n-1)$ by recognizing that $4^{n} = 4\cdot4^{n-1}$ . $\newline$ Therefore, $g(n) = -11\cdot4\cdot4^{n-1}$ . $\newline$ Since $g(n-1) = -11\cdot4^{n-1}$ , we can write $g(n)$ as $g(n)$ $0$ times $g(n-1)$ . $\newline$ Calculation: $g(n)$ $2$