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For the following sequence determine the common difference (if it is an arithmetic sequence) or the common ratio (if it is a geometric sequence).

8sqrt3,quad24,quad24sqrt3,quad dots

(sqrt3)/(3)

sqrt3

2sqrt3

(2sqrt3)/(3)

For the following sequence determine the common difference (if it is an arithmetic sequence) or the common ratio (if it is a geometric sequence).\newline83,24,243, 8 \sqrt{3}, \quad 24, \quad 24 \sqrt{3}, \quad \ldots \newline33 \frac{\sqrt{3}}{3} \newline3 \sqrt{3} \newline23 2 \sqrt{3} \newline233 \frac{2 \sqrt{3}}{3}

Full solution

Q. For the following sequence determine the common difference (if it is an arithmetic sequence) or the common ratio (if it is a geometric sequence).\newline83,24,243, 8 \sqrt{3}, \quad 24, \quad 24 \sqrt{3}, \quad \ldots \newline33 \frac{\sqrt{3}}{3} \newline3 \sqrt{3} \newline23 2 \sqrt{3} \newline233 \frac{2 \sqrt{3}}{3}
  1. Identify Sequence Type: First, let's identify whether the sequence is arithmetic or geometric. An arithmetic sequence has a common difference between terms, while a geometric sequence has a common ratio.\newlineTo determine this, we can compare the ratio of consecutive terms.\newlineLet's calculate the ratio of the second term to the first term.\newlineRatio = 2483\frac{24}{8\sqrt{3}}
  2. Calculate Ratio: Now, let's simplify the ratio.\newlineRatio = 2483=33\frac{24}{8\sqrt{3}} = \frac{3}{\sqrt{3}}
  3. Simplify Ratio: To further simplify, we can rationalize the denominator.\newlineRatio = (33)(33)=333(\frac{3}{\sqrt{3}}) \cdot (\frac{\sqrt{3}}{\sqrt{3}}) = \frac{3\sqrt{3}}{3}
  4. Check Consistency: After simplifying, we get:\newlineRatio = 333=3\frac{3\sqrt{3}}{3} = \sqrt{3}
  5. Calculate Next Ratio: Now, let's check if this ratio is consistent with the next pair of terms.\newlineWe calculate the ratio of the third term to the second term.\newlineRatio = (243)/24(24\sqrt{3}) / 24
  6. Simplify Next Ratio: Simplify the ratio.\newlineRatio = (243)/24=3(24\sqrt{3}) / 24 = \sqrt{3}
  7. Conclude Geometric Sequence: Since the ratio between consecutive terms is consistent and equal to 3\sqrt{3}, we can conclude that the sequence is geometric with a common ratio of 3\sqrt{3}.

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