Find the slope-intercept form for the line satisfying the conditions. slope -6 , passing through (0,1)

Identify Linear Equation Form: Identify the slope-intercept form of a linear equation. The slope-intercept form of a linear equation is y = mx + b, where m is the slope and b is the y-intercept.Find Y-Intercept: Use the given slope and point to find the y-intercept. Since the line passes through the point (0,1), the y-intercept (b) is 1 because when x is 0, y is 1.Substitute Slope and Y-Intercept: Substitute the slope (-6) and y-intercept (1) into the slope-intercept form. Using the slope-intercept form y = mx + b, we substitute m with -6 and b with 1 to get y = -6x + 1.

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Find the slope-intercept form for the line satisfying the conditions. $\newline$ slope $-6$ , passing through $\newline$ $(0,1)$

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Q. Find the slope-intercept form for the line satisfying the conditions.

\newline

slope

-6

, passing through

\newline

(0,1)

Identify Linear Equation Form: Identify the slope-intercept form of a linear equation. $\newline$ The slope-intercept form of a linear equation is $y = mx + b$ , where $m$ is the slope and $b$ is the y-intercept.
Find Y-Intercept: Use the given slope and point to find the y-intercept. $\newline$ Since the line passes through the point $(0,1)$ , the y-intercept $(b)$ is $1$ because when $x$ is $0$ , $y$ is $1$ .
Substitute Slope and Y-Intercept: Substitute the slope $-6$ and y-intercept $1$ into the slope-intercept form. $\newline$ Using the slope-intercept form $y = mx + b$ , we substitute $m$ with $-6$ and $b$ with $1$ to get $y = -6x + 1$ .