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Determine the following limit in simplest form. If the limit is infinite, state that the limit does not exist (DNE).

lim_(x rarr oo)(sqrt(-3x+x^(4)))/(7+8x^(2)+10 x)
Answer:

Determine the following limit in simplest form. If the limit is infinite, state that the limit does not exist (DNE).\newlinelimx3x+x47+8x2+10x \lim _{x \rightarrow \infty} \frac{\sqrt{-3 x+x^{4}}}{7+8 x^{2}+10 x} \newlineAnswer:

Full solution

Q. Determine the following limit in simplest form. If the limit is infinite, state that the limit does not exist (DNE).\newlinelimx3x+x47+8x2+10x \lim _{x \rightarrow \infty} \frac{\sqrt{-3 x+x^{4}}}{7+8 x^{2}+10 x} \newlineAnswer:
  1. Analyze Behavior of Functions: To find the limit of the function as xx approaches infinity, we need to analyze the behavior of the numerator and the denominator separately. We will look for the highest power of xx in both the numerator and the denominator to simplify the expression.
  2. Divide by Highest Power of x: In the numerator, the highest power of x is x4x^4, and in the denominator, the highest power of x is x2x^2. To simplify the limit, we can divide both the numerator and the denominator by x2x^2, the highest power of x in the denominator.
  3. Simplify Expression Inside Square Root: When we divide each term in the numerator and the denominator by x2x^2, we get: limx(x43x/x2)/(7x2+8+10x)\lim_{x \rightarrow \infty}(\sqrt{x^4 - 3x}/x^2) / (\frac{7}{x^2} + 8 + \frac{10}{x})
  4. Ignore Terms Approaching Zero: Now we simplify the expression inside the square root in the numerator by dividing each term by x2x^2: limx(x23x)/(7x2+8+10x)\lim_{x \rightarrow \infty}\left(\sqrt{x^2 - \frac{3}{x}}\right) / \left(\frac{7}{x^2} + 8 + \frac{10}{x}\right)
  5. Simplified Limit Calculation: As xx approaches infinity, the terms 3x-\frac{3}{x} and 7x2\frac{7}{x^2} in the numerator and the denominator, respectively, will approach zero. The term 10x\frac{10}{x} in the denominator will also approach zero. So we can ignore these terms for the limit calculation.
  6. Square Root of x2x^2: The simplified form of the limit is now: limx(x28)\lim_{x \rightarrow \infty}\left(\frac{\sqrt{x^2}}{8}\right)
  7. Limit Calculation Result: The square root of x2x^2 is xx, so the limit simplifies further to:\newlinelimxx8\lim_{x \rightarrow \infty}\frac{x}{8}
  8. Limit as xx Approaches Infinity: As xx approaches infinity, the limit of x8\frac{x}{8} is also infinity, since the value of xx becomes unbounded and there is no other term in the denominator to counteract this growth.
  9. Conclusion: Therefore, the limit of the function as xx approaches infinity is infinite, which means the limit does not exist (DNE).

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