Resources

Resources

Bytelearn - cat image with glasses

AI tutor

Welcome to Bytelearn!

Let’s check out your problem:

For the following equation, what is the instantaneous rate of change at
x=-2?

f(x)=2x^(2)-5
Answer:

For the following equation, what is the instantaneous rate of change at $x=-2 ?$ $\newline$ $f(x)=2 x^{2}-5$ $\newline$ Answer:

View step-by-step help

View step-by-step help

Find derivatives using logarithmic differentiation

Full solution

Q. For the following equation, what is the instantaneous rate of change at

x=-2 ?

\newline

f(x)=2 x^{2}-5

\newline

Answer:

Calculate Derivative: To find the instantaneous rate of change of the function at a specific point, we need to calculate the derivative of the function. The derivative of a function gives us the slope of the tangent line at any point, which is the instantaneous rate of change.
Apply Power Rule: The function given is $f(x) = 2x^2 - 5$ . To find its derivative, we use the power rule, which states that the derivative of $x^n$ is $n\cdot x^{(n-1)}$ . Applying this rule to our function, we differentiate each term separately.
Find Derivative of Function: Differentiating the term $2x^2$ , we get $2 \times 2x^{2-1} = 4x$ . The constant term $-5$ has a derivative of $0$ , since the derivative of any constant is $0$ .
Substitute $x = -2$ : Now we have the derivative of the function, which is $f'(x) = 4x$ . To find the instantaneous rate of change at $x = -2$ , we substitute $-2$ into the derivative.
Calculate Instantaneous Rate of Change: Substituting $x = -2$ into $f'(x) = 4x$ , we get $f'(-2) = 4*(-2) = -8$ .
Calculate Instantaneous Rate of Change: Substituting $x = -2$ into $f'(x) = 4x$ , we get $f'(-2) = 4\times(-2) = -8$ .The instantaneous rate of change of the function $f(x)$ at $x = -2$ is $-8$ .

More problems from Find derivatives using logarithmic differentiation

Question

\newline

500

=

Posted 9 months ago

Question

\newline

2,000

=

Posted 9 months ago

Question

\newline

750

=

Posted 9 months ago

Question

\newline

1,500

=

Posted 9 months ago

Question

\newline

1,500

=

Posted 9 months ago

Question

According to Newton's Second Law of Motion, the sum of the forces that act on an object with a mass

m

that moves with an acceleration

a

m \cdot a

. An object whose mass is

80

grams has an acceleration of

20

meters per seconds squared. What calculation will give us the sum of the forces that act on the object, in Newtons (which are

\frac{\text{kg} \cdot \text{m}}{\text{s}^2}

\newline

1

\newline

80 \cdot 20

\newline

80 \cdot 1000 \cdot 20

\newline

\frac{80}{1000} \cdot 20

\newline

\frac{80}{60^2} \cdot 20

Posted 8 months ago

Question

\newline

Multiply and remove all perfect squares from inside the square roots. Assume

\newline

b

\newline

2\sqrt{8b^{3}} \cdot 9\sqrt{18b} =

Posted 10 months ago

Question

Roselyn is driving to visit her family, who live

150

kilometers away. Her average speed is

60

kilometers per hour. The car's tank has

20

liters of fuel at the beginning of the drive, and its fuel efficiency is

6

kilometers per liter. Fuel costs

0.60

dollars per liter.

\newline

How long can Roselyn drive before she runs out of fuel?

\newline

Posted 10 months ago

Question

Astrid is in charge of building a new fleet of ships. Each ship requires

40

tons of wood, and accommodates

300

sailors. She receives a delivery of

4

tons of wood each day. The deliveries can continue for

100

days at most, afterwards the weather is too bad to allow them. Overall, she wants to build enough ships to accommodate at least

2100

\newline

How much wood does Astrid need to accommodate

2100

\newline

Posted 10 months ago

Question

Lily's car has a fuel efficiency of

8 \text{ liters}

100 \text{ kilometers}

\newline

What is the fuel efficiency of Lily's car in

\text{kilometers}

\text{liter}

\newline

\frac{\text{km}}{\text{L}}

Posted 10 months ago

Related topics

Algebra - Order of Operations Algebra - Distributive Property `X` and `Y` Axes Geometry - Scalene Triangle Common Multiple Geometry - Quadrant