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Find the sum of the infinite geometric series.\newline2+32+98+2732+2 + \frac{3}{2} + \frac{9}{8} + \frac{27}{32} + \dots\newlineWrite your answer as an integer or a fraction in simplest form.\newline__\_\_

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Q. Find the sum of the infinite geometric series.\newline2+32+98+2732+2 + \frac{3}{2} + \frac{9}{8} + \frac{27}{32} + \dots\newlineWrite your answer as an integer or a fraction in simplest form.\newline__\_\_
  1. Identify Terms and Ratio: To find the sum of an infinite geometric series, we need to identify the first term aa and the common ratio rr of the series. The formula for the sum of an infinite geometric series is S=a1rS = \frac{a}{1 - r}, where |r| < 1. In the given series, the first term is 22 and each subsequent term is multiplied by 34\frac{3}{4} (for example, 32\frac{3}{2} is 34\frac{3}{4} of 22, 98\frac{9}{8} is 34\frac{3}{4} of 32\frac{3}{2}, and so on). Therefore, rr22 and rr33.
  2. Apply Sum Formula: Now we apply the formula for the sum of an infinite geometric series: S=a1rS = \frac{a}{1 - r}. Substitute the values of aa and rr into the formula: S=2134S = \frac{2}{1 - \frac{3}{4}}.
  3. Simplify Expression: Next, we simplify the expression: S=2134=24434=214S = \frac{2}{1 - \frac{3}{4}} = \frac{2}{\frac{4}{4} - \frac{3}{4}} = \frac{2}{\frac{1}{4}}.
  4. Calculate Sum: Finally, we calculate the sum: S=2(14)=2×(41)=8S = \frac{2}{\left(\frac{1}{4}\right)} = 2 \times \left(\frac{4}{1}\right) = 8. The sum of the infinite geometric series is 88.

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