Q. Find the sum of the geometric series1−3+32−33+…−329Choose 1 answer:(A) −1.03⋅1014(B) −6.86⋅1013(C) −5.15⋅1013(D) 1.72⋅1013
Identify Geometric Series: The given series is a geometric series with the first term a=1 and the common ratio r=−3. The sum of a finite geometric series can be calculated using the formula Sn=1−ra(1−rn), where n is the number of terms.
Determine Number of Terms: First, we need to determine the number of terms in the series. Since the series starts at 30 (which is 1) and goes up to 329, and the powers of 3 increase by 1 each time, there are 30 terms in total.
Apply Sum Formula: Now we can apply the formula for the sum of a geometric series: Sn=a(1−rn)/(1−r). Here, a=1, r=−3, and n=30.
Calculate Numerator: Plugging the values into the formula, we get S30=1−(−3)1(1−(−3)30).
Calculate Denominator: Calculating the numerator: 1−(−3)30=1−330. Since 330 is a very large number, we can leave it in the exponential form for now.
Substitute Values: Calculating the denominator: 1−(−3)=1+3=4.
Calculate Exponential Value: Now we have S30=41−330. To find the exact value of 330, we can use a calculator or a computer.
Perform Subtraction: Using a calculator, we find that 330 is approximately 2.05×1014.
Divide by 4: Substituting this value into our sum expression, we get S30=4(1−2.05×1014).
Express in Scientific Notation: Now we perform the subtraction in the numerator: 1−2.05×1014=−2.05×1014+1. Since 1 is negligible compared to 2.05×1014, we can approximate this as −2.05×1014.
Express in Scientific Notation: Now we perform the subtraction in the numerator: 1−2.05×1014=−2.05×1014+1. Since 1 is negligible compared to 2.05×1014, we can approximate this as −2.05×1014.Finally, we divide by 4: S30=−2.05×1014/4=−0.5125×1014.
Express in Scientific Notation: Now we perform the subtraction in the numerator: 1−2.05×1014=−2.05×1014+1. Since 1 is negligible compared to 2.05×1014, we can approximate this as −2.05×1014.Finally, we divide by 4: S30=−2.05×1014/4=−0.5125×1014.We can write −0.5125×1014 in scientific notation as −5.125×1013.
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