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Find the sum of the first 45 terms in this geometric series:

-0.5+1.5-4.5 dots
Choose 1 answer:
(A) 
-7.39*10^(20)
(B) 
-4.92*10^(20)
(C) 
-3.69*10^(20)
(D) 
1.23*10^(20)

Find the sum of the first 4545 terms in this geometric series:\newline0.5+1.54.5 -0.5+1.5-4.5 \ldots \newlineChoose 11 answer:\newline(A) 7.391020 -7.39 \cdot 10^{20} \newline(B) 4.921020 -4.92 \cdot 10^{20} \newline(C) 3.691020 -3.69 \cdot 10^{20} \newline(D) 1.231020 1.23 \cdot 10^{20}

Full solution

Q. Find the sum of the first 4545 terms in this geometric series:\newline0.5+1.54.5 -0.5+1.5-4.5 \ldots \newlineChoose 11 answer:\newline(A) 7.391020 -7.39 \cdot 10^{20} \newline(B) 4.921020 -4.92 \cdot 10^{20} \newline(C) 3.691020 -3.69 \cdot 10^{20} \newline(D) 1.231020 1.23 \cdot 10^{20}
  1. Identify terms and ratio: Identify the first term aa and the common ratio rr of the geometric series.\newlineThe first term a=0.5a = -0.5, and each term is multiplied by 3-3 to get the next term (since 0.5×3=1.5-0.5 \times -3 = 1.5, 1.5×3=4.51.5 \times -3 = -4.5, and so on), so the common ratio r=3r = -3.
  2. Use sum formula: Use the formula for the sum of the first nn terms of a geometric series: Sn=a(1rn)(1r)S_n = \frac{a(1 - r^n)}{(1 - r)}, where SnS_n is the sum of the first nn terms, aa is the first term, rr is the common ratio, and nn is the number of terms.\newlineHere, n=45n = 45, a=0.5a = -0.5, and r=3r = -3.
  3. Calculate denominator: Substitute the values into the formula and calculate the sum. S45=0.5(1(3)45)/(1(3))S_{45} = -0.5(1 - (-3)^{45}) / (1 - (-3))
  4. Calculate exponent: Calculate the denominator of the fraction: 1(3)=1+3=41 - (-3) = 1 + 3 = 4.
  5. Estimate numerator: Calculate (3)45(-3)^{45}. Since 4545 is an odd number, the result will be negative, and the magnitude will be 3453^{45}.
  6. Substitute values: The magnitude of 3453^{45} is a very large number, and it's not practical to calculate it exactly without a calculator. However, we can estimate that it will be a number much larger than 102010^{20}, and since it's raised to an odd power, the result will be negative.
  7. Consider magnitude: Now, calculate the numerator of the fraction: 1(3)451 - (-3)^{45}. Since (3)45(-3)^{45} is negative and its magnitude is much larger than 11, the result will be approximately equal to (3)45-(-3)^{45}.
  8. Eliminate options: Substitute the calculated values into the sum formula:\newlineS450.5×((3)45)/4S_{45} \approx -0.5 \times (-(-3)^{45}) / 4\newlineS450.5×345/4S_{45} \approx 0.5 \times 3^{45} / 4
  9. Choose closest option: Since 3453^{45} is much larger than 44, dividing by 44 will not significantly affect the magnitude of the number. Therefore, the sum will be approximately 0.5×345.0.5 \times 3^{45}.
  10. Choose closest option: Since 3453^{45} is much larger than 44, dividing by 44 will not significantly affect the magnitude of the number. Therefore, the sum will be approximately 0.5×3450.5 \times 3^{45}.Given the choices, we are looking for a negative number with a magnitude in the order of 102010^{20}. The only negative options are (A), (B), and (C).
  11. Choose closest option: Since 3453^{45} is much larger than 44, dividing by 44 will not significantly affect the magnitude of the number. Therefore, the sum will be approximately 0.5×3450.5 \times 3^{45}.Given the choices, we are looking for a negative number with a magnitude in the order of 102010^{20}. The only negative options are (A), (B), and (C).Since the sum is approximately 0.5×3450.5 \times 3^{45} and we know 3453^{45} is a very large number, we can eliminate the smallest magnitude among the negative options, which is (C) 3.69×1020-3.69\times10^{20}.
  12. Choose closest option: Since 3453^{45} is much larger than 44, dividing by 44 will not significantly affect the magnitude of the number. Therefore, the sum will be approximately 0.5×3450.5 \times 3^{45}.Given the choices, we are looking for a negative number with a magnitude in the order of 102010^{20}. The only negative options are (A), (B), and (C).Since the sum is approximately 0.5×3450.5 \times 3^{45} and we know 3453^{45} is a very large number, we can eliminate the smallest magnitude among the negative options, which is (C) 3.69×1020-3.69\times10^{20}.Between (A) and (B), we choose the one that is closest to half of 3453^{45}. Without an exact calculation, we cannot determine whether (A) 7.39×1020-7.39\times10^{20} or (B) 4400 is the correct answer. However, since we are dividing by 44 in the last step, it is more likely that the sum is closer to (B) 4400 than to (A) 7.39×1020-7.39\times10^{20}.

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