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Find the sum of the first 10 terms of the following series, to the nearest integer.

21,126,756,dots
Answer:

Find the sum of the first 1010 terms of the following series, to the nearest integer.\newline21,126,756, 21,126,756, \ldots \newlineAnswer:

Full solution

Q. Find the sum of the first 1010 terms of the following series, to the nearest integer.\newline21,126,756, 21,126,756, \ldots \newlineAnswer:
  1. Identify Series Type: Identify whether the given series is geometric or arithmetic. In the given series, each term is a multiple of the previous term, which suggests that the series is geometric.
  2. Find Common Ratio: Identify the common ratio of the geometric series.\newlineTo find the common ratio, divide the second term by the first term.\newlineCommon Ratio rr = 12621\frac{126}{21} = 66
  3. Use Sum Formula: Use the formula for the sum of the first nn terms of a geometric series.\newlineThe formula for the sum of the first nn terms (SnS_n) of a geometric series is:\newlineSn=a(1rn)/(1r)S_n = a \cdot (1 - r^n) / (1 - r), where aa is the first term and rr is the common ratio.
  4. Calculate Sum: Calculate the sum of the first 1010 terms using the formula.\newlineFirst term (a)=21(a) = 21\newlineCommon Ratio (r)=6(r) = 6\newlineNumber of terms (n)=10(n) = 10\newlineS10=21×(1610)/(16)S_{10} = 21 \times (1 - 6^{10}) / (1 - 6)
  5. Perform Calculations: Perform the calculations.\newlineS10=21×(160466176)/(16)S_{10} = 21 \times (1 - 60466176) / (1 - 6)\newlineS10=21×(60466175)/(5)S_{10} = 21 \times (-60466175) / (-5)\newlineS10=21×12093235S_{10} = 21 \times 12093235\newlineS10=253958535S_{10} = 253958535
  6. Round Sum: Round the sum to the nearest integer.\newlineThe sum is already an integer, so no rounding is necessary.

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