Q. Find the slope of the tangent line to the graph of x=−y3+8y2−59 at (5,4).
Find Derivative of x: First, we need to find the derivative of x with respect to y to get the slope of the tangent line. Since x=−y3+8y2−59, differentiate each term with respect to y.dydx=−3y2+16y
Substitute y=4: Next, substitute y=4 into the derivative to find the slope at that specific point.dydx at y=4 = −3(4)2+16(4)=−48+64=16
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