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Find the slope of the tangent line to the graph of x=4y39x = 4y^3 - 9 at (5,1)(-5,1).

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Q. Find the slope of the tangent line to the graph of x=4y39x = 4y^3 - 9 at (5,1)(-5,1).
  1. Find Derivative of xx: First, we need to find the derivative of xx with respect to yy to get the slope of the tangent line. Since x=4y39x = 4y^3 - 9, differentiate both sides with respect to yy.dxdy=12y2\frac{dx}{dy} = 12y^2
  2. Substitute y=1y = 1: Next, substitute y=1y = 1 into the derivative to find the slope at the specific point.\newlineSlope = 12×(1)2=1212\times(1)^2 = 12

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