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Find the domain of\newliney=x+34x29y=\frac{x+3}{4-\sqrt{x^{2}-9}}

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Q. Find the domain of\newliney=x+34x29y=\frac{x+3}{4-\sqrt{x^{2}-9}}
  1. Identify Restrictions: Identify the restrictions for the denominator, since division by zero is undefined.\newline4x2904 - \sqrt{x^2 - 9} \neq 0
  2. Solve Denominator: Solve for xx where the denominator equals zero.x29=4\sqrt{x^2 - 9} = 4
  3. Square Root Elimination: Square both sides to eliminate the square root. (x29)=16 (x^2 - 9) = 16
  4. Move to Right Side: Move 99 to the right side.\newlinex2=25x^2 = 25
  5. Take Square Root: Take the square root of both sides.\newlinex=±5x = \pm 5
  6. Check Solutions: Since we squared during our steps, we need to check if these solutions don't cause the original denominator to be zero.\newlinePlug x=5x = 5 and x=5x = -5 back into the original denominator.\newline4529=416=44=04 - \sqrt{5^2 - 9} = 4 - \sqrt{16} = 4 - 4 = 0\newline4(5)29=416=44=04 - \sqrt{(-5)^2 - 9} = 4 - \sqrt{16} = 4 - 4 = 0\newlineBoth x=5x = 5 and x=5x = -5 make the denominator zero, so they are not in the domain.
  7. Identify Square Root Restrictions: Identify the restrictions for the square root in the denominator, since square roots are only defined for non-negative numbers. x290x^2 - 9 \geq 0
  8. Factor and Solve: Factor the left side.\newline(x+3)(x3)0(x + 3)(x - 3) \geq 0
  9. Find Intervals: Find the intervals where the inequality is satisfied. x3x \leq -3 or x3x \geq 3
  10. Combine Restrictions: Combine the restrictions from the denominator and the square root.\newlineThe domain is all xx such that x3x \leq -3 or x3x \geq 3, but not including x=5x = 5 or x=5x = -5.

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